b^2-10b+60=0

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Solution for b^2-10b+60=0 equation:


Simplifying
b2 + -10b + 60 = 0

Reorder the terms:
60 + -10b + b2 = 0

Solving
60 + -10b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-60' to each side of the equation.
60 + -10b + -60 + b2 = 0 + -60

Reorder the terms:
60 + -60 + -10b + b2 = 0 + -60

Combine like terms: 60 + -60 = 0
0 + -10b + b2 = 0 + -60
-10b + b2 = 0 + -60

Combine like terms: 0 + -60 = -60
-10b + b2 = -60

The b term is -10b.  Take half its coefficient (-5).
Square it (25) and add it to both sides.

Add '25' to each side of the equation.
-10b + 25 + b2 = -60 + 25

Reorder the terms:
25 + -10b + b2 = -60 + 25

Combine like terms: -60 + 25 = -35
25 + -10b + b2 = -35

Factor a perfect square on the left side:
(b + -5)(b + -5) = -35

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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